Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Trigonometric Identities - Section 5.5 Double-Angle Identities - 5.5 Exercises - Page 238: 70a

Answer

$W = 200.49~sin^2~120\pi t$ We can see a sketch of the graph in the window $[0,0.05]$ by $[-50,300]$
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Work Step by Step

$W = VI$ $W = (163~sin~120\pi t)(1.23~sin~120\pi t)$ $W = 200.49~sin^2~120\pi t$ We can see a sketch of the graph in the window $[0,0.05]$ by $[-50,300]$
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