Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Trigonometric Identities - Section 5.4 Sum and Difference Identities for Sine and Tangent - 5.4 Exercises - Page 227: 50


$A$, $B$ and $C$ being 3 angles of a triangle means that the sum of them equals $180^\circ$. Therefore, $\sin(A+B+C)$ equals $\sin180^\circ$, which equals $0$.

Work Step by Step

If $A$, $B$ and $C$ are the 3 angles of a triangle, that means $$A+B+C=180^\circ$$ Therefore, $$\sin(A+B+C)=\sin180^\circ=0$$
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