Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 250: 71b


The stone will travel 35 feet.

Work Step by Step

In part (a), when $h=0$: $D = \frac{v^2~sin~(2~\theta)}{32}$ We can find $D$ when $\theta = 30^{\circ}$ and $v = 36~ft/s$: $D = \frac{(36~ft/s)^2~sin~[(2)(30^{\circ})]}{32}$ $D = \frac{(36~ft/s)^2~sin~(60^{\circ})}{32}$ $D = 35~ft$ The stone will travel 35 feet.
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