## Trigonometry (11th Edition) Clone

$$\tan(-35^\circ)=\cot125^\circ$$ 19 is matched with H.
$$\tan(-35^\circ)$$ We know that $125^\circ-35^\circ=90^\circ$. Now remind yourself of Cofunction Identity for tangent and cotangents, which state $$\tan\theta=\cot(90^\circ-\theta)$$ Thus, $$\tan(-35^\circ)=\cot[90^\circ-(-35^\circ)]$$ $$\tan(-35^\circ)=\cot(90^\circ+35^\circ)$$ $$\tan(-35^\circ)=\cot125^\circ$$ which corresponds to choice H. Thus, 19 is matched with H.