Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Review Exercises - Page 192: 53b



Work Step by Step

According to the question, July 1 of the base year is represented by $x=0.5$. Therefore, we substitute $x=0.5$ in the equation to find the pollution level y on the aforementioned date: $y=7(1-\cos2\pi x)(x+10)+100e^{0.2x}$ $y=7[1-\cos2\pi (0.5)](0.5+10)+100e^{0.2\times0.5}$ $y=7(1-\cos \pi)(10.5)+100e^{0.1}$ $y=7[1-(-1)](10.5)+100(1.1052)$ $y=7(2)(10.5)+110.52$ $y=147+110.52$ $y=257.52\approx258$ Therefore, the pollution level on July 1 of the base year is 258.
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