Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Review Exercises - Page 191: 51f



Work Step by Step

Since October is represented by $x=9$, we substitute $x=9$ in the equation to find the value of $t$: $t=60-30\cos\frac{x\pi}{6}$ $t=60-30\cos\frac{9\pi}{6}$ $t=60-30\cos\frac{3\pi}{2}$ $t=60-30(0)$ $t=60-0$ $t=60$ Therefore, the maximum afternoon temperature for the month of October is 60$^{\circ}$F.
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