Answer
$tan(-x) = -tan~x$
Work Step by Step
$tan(-x) = \frac{sin~(-x)}{cos~(-x)}$
$tan(-x) = \frac{-sin~(x)}{cos~(x)}$
$tan(-x) = -\frac{sin~(x)}{cos~(x)}$
$tan(-x) = -tan~x$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 4 - Graphs of the Circular Functions - Section 4.3 Graphs of the Tangent and Cotangent Functions - 4.3 Exercises - Page 172: 51
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