#### Answer

$tan(-x) = -tan~x$

#### Work Step by Step

$tan(-x) = \frac{sin~(-x)}{cos~(-x)}$
$tan(-x) = \frac{-sin~(x)}{cos~(x)}$
$tan(-x) = -\frac{sin~(x)}{cos~(x)}$
$tan(-x) = -tan~x$

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Published by
Pearson

ISBN 10:
978-0-13-421743-7

ISBN 13:
978-0-13421-743-7

$tan(-x) = -tan~x$

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