Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 3 - Review Exercises - Page 137: 62

Answer

(a) $\frac{\pi}{3}\, radians$ (b) $15\pi\,ft$ (c) $\frac{5\pi}{4}\,ft/min$

Work Step by Step

(a) $\omega=\frac{\theta}{t}\implies \theta=\omega t$ $=(\frac{\pi}{36}\,rad/min)(12\,min)=\frac{\pi}{3}\, radians$ (b) $s=r\theta= 45\,ft\times\frac{\pi}{3}$ $=15\pi\,ft$ (c) $v=r\omega=45\,ft\times\frac{\pi}{36}\,rad/min$ $=\frac{5\pi}{4}\,ft/min$
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