Answer
$32\pi$ inches.
Work Step by Step
$r=2\,in$
$t=8\,hr$
$\omega=\frac{2\pi\,rad}{60\,min}=\frac{2\pi\,rad}{1\,hr}=2\pi\,rad/hr$
$v=r\omega=(2\,in)(2\pi\,rad/hr)=4\pi\,in/hr$
$d=vt=(4\pi\,in/hr)(8\,hr)=32\pi \,in$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 3 - Review Exercises - Page 135: 20
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