Answer
$\frac{14}{15}\pi\,mm/s$
Work Step by Step
$r=28\,mm$
$\omega=\frac{\theta}{t}=\frac{2\pi\,rad}{60\,s}=\frac{\pi}{30}\,rad/s$
$v=r\omega= (28\,mm)(\frac{\pi}{30}rad/s)$
$=\frac{14}{15}\pi\,mm/s$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 3 - Radian Measure and the Unit Circle - Section 3.4 Linear and Angular Speed - 3.4 Exercises - Page 131: 38
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