#### Answer

$PQ = \frac{\sqrt{3}}{2}$

#### Work Step by Step

Let $y = PQ$:
$\frac{y}{r} = sin ~60^{\circ}$
$\frac{y}{r} = \frac{\sqrt{3}}{2}$
$y = (r)~(\frac{\sqrt{3}}{2})$
$y = (1)~(\frac{\sqrt{3}}{2})$
$y = \frac{\sqrt{3}}{2}$
$PQ = \frac{\sqrt{3}}{2}$

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Published by
Pearson

ISBN 10:
978-0-13-421743-7

ISBN 13:
978-0-13421-743-7

$PQ = \frac{\sqrt{3}}{2}$

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