## Trigonometry (11th Edition) Clone

$d=(\frac{L}{\theta})(1-\cos \frac{\theta}{2})$
Substituting the answer from 77, $r=\frac{L}{\theta}$, into the answer of 79: $d=r(1-\cos \frac{\theta}{2})$ $d=(\frac{L}{\theta})(1-\cos \frac{\theta}{2})$ This is the formula that gives $d$ for specific values of $\theta$.