#### Answer

The new area is twice the size of the original area. Since we solved the question algebraically, we can see that this result holds in general.

#### Work Step by Step

Let $\theta$ be the angle in radians. Let $A$ be the area of the sector. Then the ratio of the angle $\theta$ to $2\pi$ is equal to the ratio of the sector area to the area of the whole circle.
$\frac{\theta}{2\pi} = \frac{A}{\pi ~r^2}$
$A = \frac{\theta ~r^2}{2}$
Let the original angle be $\theta_1$ and let the original radius be $r_1$:
$A_1 = \frac{\theta_1 ~r_1^2}{2}$
We can find an expression for the new area:
$A_2 = \frac{\theta_2 ~r_2^2}{2}$
$A_2 = \frac{(\theta_1/2) ~(2r_1)^2}{2}$
$A_2 = 2\times \frac{\theta_1 ~r_1^2}{2}$
$A_2 = 2~A_1$
The new area is twice the size of the original area. Since we solved the question algebraically, we can see that this result holds in general.