Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 3 - Quiz (Sections 3.1-3.3) - Page 126: 8



Work Step by Step

RECALL: In a unit circle, $\cos{s} = x$ (Refer to Figure 13 on page 111) The terminal side of the angle $-\frac{5\pi}{6}$ can be located by moving $\frac{5\pi}{6}$ clockwise from the positive x-axis. This angle has the same terminal side as $\frac{7\pi}{6}$ and intersects intersects the unit circle at the point $(-\frac{\sqrt3}{2}, -\frac{1}{2})$. This point has $x=-\frac{\sqrt3}{2}$ and $y=-\frac{1}{2}$. Since $\sin{s}=y$, then $\sin{(-\frac{5\pi}{6})} =\sin{\frac{7\pi}{6}} = -\frac{1}{2}$
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