## Trigonometry (11th Edition) Clone

Published by Pearson

# Chapter 2 - Quiz (Sections 2.1-2.3) - Page 71: 11

#### Answer

$-1.1817633$

#### Work Step by Step

Step 1: First, we have to convert degrees and minutes to decimal degrees: $-212^{\circ}12'=-212\frac{12}{60}^{\circ}=-212.2^{\circ}$ Step 2: Since $\sec\theta=\frac{1}{\cos\theta}$, $\sec(-212.2)=\frac{1}{\cos(-212.2)}$ Step 3: Typing $\frac{1}{\cos(-212.2)}$ and solving, we find that: $\frac{1}{\cos(-212.2)}\approx-1.1817633$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.