## Trigonometry (11th Edition) Clone

$-1.1817633$
Step 1: First, we have to convert degrees and minutes to decimal degrees: $-212^{\circ}12'=-212\frac{12}{60}^{\circ}=-212.2^{\circ}$ Step 2: Since $\sec\theta=\frac{1}{\cos\theta}$, $\sec(-212.2)=\frac{1}{\cos(-212.2)}$ Step 3: Typing $\frac{1}{\cos(-212.2)}$ and solving, we find that: $\frac{1}{\cos(-212.2)}\approx-1.1817633$