Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 88: 33

Answer

$x\approx 5.32 m$

Work Step by Step

$\tan 18^{\circ} 10' =\frac{h}{28}$ $\tan 27^{\circ} 10' =\frac{x+h}{28}$ $28\tan 18^{\circ} 10' =h$ $x = 28\tan 27^{\circ} 10' - h$ $x = 28\tan 27^{\circ} 10' - 28\tan 18^{\circ} 10'\approx 5.181574856\approx5.32m$
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