Answer
2202.6 ft
Work Step by Step
$\angle A = 90 ^{\circ} -58^{\circ} 22' = 31^{\circ} 38'$
$AB = 2587 ft$ [in a right-angles trinagle]
Apply cosine definition
$\cos (31^{\circ} 38') =\frac{x}{2587} $
$x\approx 2202.6 ft$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 87: 23
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