## Trigonometry (11th Edition) Clone

We can convert the angle to degrees: $\theta = 13^{\circ}50' = (13+\frac{50}{60})^{\circ} = 13.833^{\circ}$ Let $h$ be the height of the airplane. We can use $h$ and $\theta$ to find the horizontal distance $d$ the airplane must fly: $\frac{h}{d} = tan(\theta)$ $d = \frac{h}{tan~\theta}$ $d = \frac{10,500~ft}{tan~(13.833^{\circ})}$ $d = 42,642~ft$ The airplane needs to fly a horizontal distance of 42,642 feet to be directly over the tree.