Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 56: 83

Answer

The sides of the triangle that give the coordinates of point $P$ are the opposite and adjacent sides to the central angle. The coordinates are $P=(2\sqrt 2, 2\sqrt 2)$.

Work Step by Step

To form point $P$, we trace a line from the x and y axis until a right triangle is formed. This lines would be the opposite and adjacent sides from the $45^{\circ}$ angle. To calculate the coordinates of $P$, remember the formula for polar coordinates: $P=(r\cos\theta, r\sin\theta)$ In this case, $r=4$ and $\theta=45^{\circ}$ Substituting in the formula, $P=(4\cos(45^{\circ}), 4\sin(45^{\circ}))$ $P=(4*\frac{\sqrt 2}{2}, 4*\frac{\sqrt 2}{2})$ $P=(2\sqrt 2, 2\sqrt 2)$
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