Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 55: 67

Answer

$y =\frac{\sqrt 3}{3} x$

Work Step by Step

1. Definition of tangent $\tan\theta=\frac{y}{x}$ 2. Special angle value $\tan 30^{\circ}=\frac{\sqrt 3}{3}$ 3. Using two points we can find the equation of a line $p_1(0,0)$ and $p_2(3,\sqrt 3)$ 4. Fins a slope of the line as shown below $slope = \frac{\sqrt 3 - 0}{3-0} = \frac{\sqrt 3}{3}$ 5. Find y-intercept since it goes through the origin, $y_{intercept}= 0$ 6. Write the equation in form $y=mx+b$ $y =\frac{\sqrt 3}{3} x$
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