Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Trigonometric Functions - Section 1.1 Angles - 1.1 Exercises - Page 7: 21

Answer

a. 39°19'10" b. 159°49' 30"

Work Step by Step

a. 90° - 50°40'50" = 39°19'10" b. 180° - 50°40'50" = 129°19'10"
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.