Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Review Exercises - Page 44: 25


$\sin\theta=\frac{y}{r}=\frac{-\sqrt 3}{2}$ $\cos\theta=\frac{x}{r}=\frac{1}{2}$ $\csc\theta=\frac{r}{y}=\frac{2}{-\sqrt 3}=-\frac{2\sqrt 3}{3}$ $\sec\theta=\frac{r}{x}=\frac{2}{1}= 2$ $\tan\theta=\frac{y}{x}=\frac{-\sqrt 3}{1}=-\sqrt 3$ $\\cot\theta=\frac{x}{y}=\frac{1}{-\sqrt 3}=-\frac{\sqrt 3}{3}$

Work Step by Step

$y=\sqrt 3; x=1$ $r=\sqrt {x^{2}+y^{2}}=\sqrt {(-\sqrt 3)^{2}+(1)^{2}}=\sqrt {4}=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.