Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Quiz (Sections 1.1-1.2) - Page 21: 5



Work Step by Step

After some simplification, $(-14x+18)^{\circ}$ and $(-6x+2)^{\circ}$ become interior angles on the same side of the transversal. Therefore, $(-14x+18)^{\circ}+(-6x+2)^{\circ}=180^{\circ}$ $-14x-6x+18+2=180$ $-20x+20=180$ $-20x=160$ Therefore, $x=-8$ As a result, $(-14x+18)^{\circ}=-14(-8)+18=130^{\circ}$ $(-6x+2)^{\circ}=-6(-8)+2=50^{\circ}$
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