Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Appendix C - Functions - Page 437: 42

Answer

$-\frac{1}{16}$

Work Step by Step

We are given that $g(x)=-x^{2}+4x+1$. We can plug the given value into the equation and evaluate. $g(-\frac{1}{4})=-(-\frac{1}{4})^{2}+4(-\frac{1}{4})+1=-(\frac{1}{16})+(-1)+1=-\frac{1}{16}-1+1=-\frac{1}{16}+0=-\frac{1}{16}$
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