Answer
See below.
Work Step by Step
If we want to use ANOVA, then the ratio of the maximum and minimum standard deviation can be at most $2$. Here it is: $\frac{8.316}{7.409}\approx1.1224\lt2$, so we can use it.
The null hypothesis says that all population means are equal to each other:
$H_0:\mu_1=\mu_2=\mu_3=\mu_4$
The alternative hypothesis says the opposite of the null hypothesis, which is that at least one of the means doesn't equal all the others.
If the P-value is less than $\alpha$, which is the significance level, then this means the rejection of the null hypothesis and that the test is statistically significant.
$P\lt 0.05$, thus we reject the null hypothesis. Thus there is sufficient evidence to support the claim that the sample means in the four groups differ.
Group 1 has the highest average.
