Answer
$\mu=180$
$\rho=24$
$maximun=230$
$IQR=16$
Work Step by Step
$Fine=100+(y-20)\times5$, where y is the speed of a speeder.
$\mu=100+(28-20)\times10=180$
$\rho=2.4\times10=24$
$maximun=100+(33-20)\times10=230$
$IQR=3.2\times105=32$