Stats Modeling the World, 4th Edition

Published by Pearson
ISBN 10: 0133151549
ISBN 13: 978-0-13315-154-1

Chapter 14 - Probability Rules! - Exercises - Page 384: 15

Answer

a. 0.202 b. 0.696 c. 0.2404 d. 0.0402

Work Step by Step

a. P(USA) = $\frac{1557}{7690}$ = 0.202 b. P(high school or lower) = P(high school) + P(primary) = $\frac{4195}{7690} + \frac{1161}{7690}$ = 0.696 c. P(France or postgrad) = P(France) + P(postgrad) - P(France and postgrad)= $\frac{1539}{7690} + \frac{379}{7690} - \frac{69}{7690}$ = 0.2404 d. P(France and primary) = $\frac{309}{7690}$ = 0.0402
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