Answer
See below.
Work Step by Step
$\mu=0.1$
$\sigma=\sqrt{\frac{pq}{n}}=\sqrt{\frac{0.1(0.9)}{500}}\approx0.01342$
The sample proportion of $0.12$ is $1.49$ standard deviations away, thus it is not that unlikely.
Stats: Data and Models (3rd Edition)
by De Vaux, Richard D.; Velleman, Paul D.; Bock, David E.
Published by
Pearson
ISBN 10:
0321692551
ISBN 13:
978-0-32169-255-9
Chapter 18 - Sampling Distribution Models - Exercises - Page 451: 10
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