Stats: Data and Models (3rd Edition)

$P(Republican|male)=\frac{P(\text{Republican and male)}}{P(male)}=\frac{36/202}{105/202}=\frac{36}{105}=\frac{12}{35}\approx0.3429=34.29\%$ $P(Republican )=\frac{45+33}{202}=\frac{78}{202}\approx0.3861=38.61\%$ Thus, no, because the probabilities are not the same.