Answer
$t_{0.99} = -2.552$
Work Step by Step
df = 18
Since area is in the left tail: P(T > t) = 1 - 0.01 = 0.99
Using Table-VI, we have:
$t_{0.99} = -2.552$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 9 - Section 9.2 - Assess Your Understanding - Vocabulary and Skill Building - Page 447: 7c
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