Answer
P(p̂ > 0.3) = 0.3121. This implies that about 3 out of 100 samples of size n = 500 have more than 30% individuals who do not have a credit card.
Work Step by Step
Using data from part a for p̂ > 0.3, we have:
$z = \frac{0.3 - 0.29}{0.02} = 0.49$
P(p̂ > 0.3) = P(z > 0.49) = 0.3121
