Answer
$proportion=0.215$ (other answers are also possible)
This result is close to the result obtained in part (b).
Work Step by Step
In EXCEL, select A1, type "=RAND()" and press Enter.
Select A1 and drag down the formula "=RAND()" from A1 to A200.
In B1 enter "=COUNTIF(A1:A200;"< 0.2")"
The number of randomly generated numbers between 0 and 0.2 will be displayed.
In my case, there are 43 numbers between 0 and 0.2. So:
$proportion=\frac{43}{200}=0.215$
