Answer
0.5274
Work Step by Step
Let's find the z-scores for 80 and 100 cm:
$z=\frac{X-μ}{σ}=\frac{80-92.5}{13.7}=-0.91$
$z=\frac{X-μ}{σ}=\frac{100-92.5}{13.7}=0.55$
According to Table V, the area to the left of the standard normal curve for a z-score equal to -0.91 is 0.1814.
According to Table V, the area to the left of the standard normal curve for a z-score equal to 0.55 is 0.7088.
The area of the standard normal curve between the z-scores -0.91 and 0.55 is the difference between the area to the left of the standard normal curve for a z-score equal to 0.55 and the area to the left of the standard normal curve for a z-score equal to -0.91:
$0.7088-0.1814=0.5274$
