Answer
P(15) = 0.0520
Work Step by Step
Using formula $P(x) = _{n}C_{x}p^{x}(1-p)^{(n-x)}$, we have:
P(12) = $_{25}C_{15}0.45^{15}(1-0.45)^{(25-15)}$
= 3268760 . 0.000006 . 0.0025
= 0.0520
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