Answer
$P(X\geq8)=0.05$. It can be considered an unusual event.
Work Step by Step
$μ_X+2σ=3.3+2\times2.3=7.9$
$P(X\geq8)=P(8)+P(9)+P(10)+P(20)=0.01875+0.0125+0.0125+0.00625=0.05$
Since $P(X\geq8)\leq0.05$, it can be considered an unusual event.
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 6 - Section 6.1 - Assess Your Understanding - Applying the Concepts - Page 333: 37f
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