Answer
$μ_X=Σ[x.P(x)]=3.21$
If we randomly select a large number of households, we would expect to find about 3.21 televisions per household.
Work Step by Step
$μ_X=Σ[x.P(x)]=0\times P(0)+1\times P(1)+2\times P(2)+3\times P(3)+4\times P(4)+5\times P(5)+6\times P(6)+7\times P(7)+8\times P(8)+9\times P(9)=0\times0+1\times0.161+2\times0.261+3\times0.176+4\times0.186+5\times0.116+6\times0.055+7\times0.025+8\times0.010+9\times0.010=3.21$
