Answer
$P(F~|E)=\frac{0.4}{0.9}\approx0.4444$
Work Step by Step
Using the Conditional Probability Rule (page 288):
$P(F~|E)=\frac{P(E~and~F)}{P(E)}=\frac{0.4}{0.9}\approx0.4444$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 5 - Section 5.6 - Assess Your Understanding - Vocabulary and Skill Building - Page 311: 14
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