Answer
$P(E)=\frac{11}{250}=0.044$
Work Step by Step
1) It is a single event.
2) The outcomes are equally likely.
Use the classical method (page 259):
Sample space: 500 randomly selected Americans. So, $N(S)=500$
Let $E$ be the event "play soccer". So, $N(E)=22$
$P(E)=\frac{N(E)}{N(S)}=\frac{22}{500}=\frac{11}{250}=0.044$
