Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.5 - Assess Your Understanding - Vocabulary and Skill Building - Page 305: 17

Answer

$_8P_3=336$

Work Step by Step

RECALL: $_nP_r = \dfrac{n!}{(n-r)!}$ Use this definition to have: $\require{cancel} _8P_3=\dfrac{8!}{(8-3)!} \\_8P_3=\dfrac{8!}{5!} \\_8P_3 = \dfrac{8(7)(6)(5!)}{5!} \\_8P_3 = \dfrac{8(7)(6)\cancel{(5!)}}{\cancel{5!}} \\_8P_3=336$
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