Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.4 - Assess Your Understanding - Applying the Concepts - Page 292: 12

Answer

$P(king)=\frac{1}{13}\approx0.077$ $P(king~|~heart)=\frac{1}{13}\approx0.077$ The events "the card drawn is a king" and "the card is a heart" are independent.

Work Step by Step

The sample space: all the 52 cards from a standard 52-card deck. So, N(S) = 52. There are 4 king cards. So N(king) = 4. We can compute the probability that the card drawn is a king using the Classical Method (see page 259): $P(king)=\frac{N(king)}{N(S)}=\frac{4}{52}=\frac{1}{13}\approx0.077.$ There are 13 heart cards. So, N(heart) = 13. There is only one king among the heart cards. So, N(king and heart) = 1. Now, using the Conditional Probability Rule (see page 288): $P(king~|~heart)=\frac{N(king~and~heart)}{N(heart)}=\frac{1}{13}\approx0.077.$ $P(king~|~heart)=P(king)$. It means that the events "the card drawn is a king" and "the card is a heart" are independent.
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