Answer
$P(male~or~bet)=0.548$
Work Step by Step
$10.6$% $=0.106$, $48.4$% $=0.484$ and $17$% $=0.17$
$P(male~and~bet)=0.106$
Using the General Addition Rule (page 273):
$P(male~or~bet)=P(male)+P(bet)-P(male~and~bet)=0.484+0.17-0.106=0.548$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 5 - Section 5.3 - Assess Your Understanding - Applying the Concepts - Page 286: 32d
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