## Statistics: Informed Decisions Using Data (4th Edition)

$P(male~or~bet)=0.548$
$10.6$% $=0.106$, $48.4$% $=0.484$ and $17$% $=0.17$ $P(male~and~bet)=0.106$ Using the General Addition Rule (page 273): $P(male~or~bet)=P(male)+P(bet)-P(male~and~bet)=0.484+0.17-0.106=0.548$