Answer
$P(4~ones)=\frac{1}{1296}\approx0.000772$
If we roll a fair six-sided die four times one million different times, we would expect to observe 4 ones in a row about 772 times.
Work Step by Step
$P(one)=\frac{1}{6}$
Now, using the Multiplication Rule. Events. See page 282.
$P(4~ones)=$
$P(one~on~die~1~and~one~on~die~2~and~one~on~ die~3~and~one~on~die~4)=$
$P(one~on~die~1)\times P(one~on~die~2)\times P(one~on~die~3)\times P(one~on~die~4)=[P(one)]^{4}=(\frac{1}{6})^{4}=\frac{1}{1296}\approx0.000772$
