Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.2 - Assess Your Understanding - Applying the Concepts - Page 280: 47h

Answer

$P(reported~injuries)=\frac{289}{1121}\approx0.2578$

Work Step by Step

For the current system: The sample space: 1121 crashes. So, $N(S)=1121$ $N(reported~injuries)=289$ Using the Classical Method (page 259): $P(reported~injuries)=\frac{N(reported~injuries)}{N(S)}=\frac{289}{1121}\approx0.2578$
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