Answer
Bob has supposed that the experiment has equally likely outcomes, but it does not.
Work Step by Step
Bob’s reasoning: $P(2)=P(3)=P(4)=P(5)=P(6)=P(7)=P(8)=P(9)=P(10)=P(11)=P(12)$
The correct reasoning: $P(7)\gt P(8)=P(6)\gt P(9)=P(5)\gt P(10)=P(4)\gt P(11)=P(3)\gt P(12)=P(2)$
