Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.1 - Assess Your Understanding - Applying the Concepts - Page 268: 54c

Answer

$P(flushing~|~viagra)=\frac{73}{734}\approx0.0995\gt0.05$. So, we can conclude that "a subject from the Viagra group reported experiencing flushing" is not an unusual event.

Work Step by Step

The Viagra group sample has 734 subjects. So, $N(S)=734$. Event = "subject from the Viagra group reported experiencing flushing". $N(E)=73$. Using the Classical Method: $P(E)=P(flushing~|~viagra)=\frac{N(E)}{N(S)}=\frac{73}{734}\approx0.0995\gt0.05$
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