Answer
Yes, this observation is influential.
Work Step by Step
In MINITAB, enter the temperature values in C1 and in C2 enter the chirps per second values. Use all the values in the data given in problem 1 and add the new values given in problem 2.
Select Stats -> Regression -> Regression -> Fit Regression Model
Enter C2 in "Responses" and C1 in "Continuous Predictors"
The new least-squares regression line ($ŷ =b_1x+b_0$) will be shown in "Regression Equation", where C2 is $ŷ $ (chirps per second) and C1 is $x$ (temperature).
$ŷ _{new}=0.1431x+4.96$
Now, compare with the least-squares regression line found in problem 1 (e): $ŷ =0.2119x−0.31$
Both the slope and y-intercept have changed substantially.
