Answer
$Lower~fence=6.225~g/dL$
$Upper~fence=14.025~g/dL$
$5.7~g/dL$ in an outlier.
Work Step by Step
$Lower~fence=Q1−1.5\times IQR=9.15-1.5\times1.95=6.225$
$Upper~fence=Q3+1.5\times IQR=11.1+1.5\times1.95=14.025$
There is no data value greater than 14.025. But, $5.7\lt6.225$, so it is an outlier.
