Answer
$IQR=1.95~g/dL$
It is the range of the middle 50% values of the given data. In this case, it contains the 10 middle observations: 9.4, 9.5, 9.6, 9.6, 9.9, 10.0, 10.3, 10.6, 10.7, 11.0
Work Step by Step
$IQR=Q_3-Q_1=11.1-9.15=1.95$
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