Answer
The shape of car 1 is positively skewed, and three outliers are present and the center of car1 is 223.47, and the spread of car1 is 21.8.
The shape of the car 2 is positively skewed and the center of car 2 is 237.2, and the spread of car1 is 49.1 (188.1, 286.3).
For car 1: Mean distance = 223.47 units and spread = 21.80 units.
For car 2: Mean distance = 237.20 units and spread = 49.10 units.
Work Step by Step
Use MINITAB to determine the shape of the car. Follow the steps provided below:
Step 1: Enter the provided data in a spreadsheet.
Step 2: Select Graph > Box plot > Simple > OK.
Step 3: Transform car 1 data into graph variables.
Step 4: Click on OK.
The obtained output is displayed. From the obtained output, it is observed that the data is positively skewed and three outliers are present in the data.
Use MINITAB to determine the shape of the car. Follow the steps provided below:
Step 1: Enter the provided data in a spreadsheet.
Step 2: Select Stat>Basic Statistics >Display Descriptive Statistics.
Step 3: Transform the car 1 data into variables.
Step 4: Click OK.
The obtained output is displayed. From the obtained output, it is observed that the mean of the data is 223.47, and the spread of the data is 21.8 (201.67, 245.27).
Use MINITAB to determine the shape of the car. Follow the steps provided below:
Step 1: Enter the provided data in a spreadsheet.
Step 2: Select Graph>Boxplot>Simple and click on OK.
Step 3: Transform the car 2 data into graph variables.
Step 4: Click on OK.
The obtained output is displayed. From the obtained output, it is observed that the shape of the car is positively skewed.
Use MINITAB to determine the shape of the car. Follow the steps provided below:
Step 1: Enter the provided data in a spreadsheet.
Step 2: Select Stat>Basic Statistics >Display Descriptive Statistics.
Step 3: Transform the car 2 data into variables.
Step 4: Click on OK.
The obtained output is displayed. From the obtained output, it is observed that the mean of the data is 237.2, and the spread of the data is 49.1.
We will choose car 1 as the spread of the car 1 is less as compared to the car 2, which means the best estimate of its mileage will lie more near to the mean distance for car 1 as compared to the car 2.
