Answer
$Mean\lt Median$
This contradicts the rule that says that, in a skewed-right distribution, the mean is greater than the median.
Work Step by Step
$Mean=\frac{23\times0+17\times1+4\times2+3\times3+2\times4+1\times5}{50}=0.94$
There are 50 observations (even). According to the histogram (in ascending order), the 25th and 26th number of days are 1 and 1.
$Median=\frac{1+1}{2}=1$
Notice that, if you change two number of days from 1 to 0, there will be 25 number of days equal to 0 and 15 number of days equal to 1. And then: $median=\frac{0+1}{2}=0.5$
And if you change three number of days from 1 to 0, there will be 26 number of days equal to 0 and 14 number of days equal to 1. Now, $median=0$
That is the "problem" for some discrete data.
